Changed database to a more reliable one, added functionality for no three word puzzles.

find_words.py

@@ -1,6 +1,6 @@
 # Find words based on letters given
 
-from read_english_dictionary import load_words
+from import_dictionary import load_words
 from sys import argv
 
 def create_bank(letters):
@@ -13,11 +13,15 @@ def create_bank(letters):
   
   return lb
 
-def main(letters):
+def main(letters, no_three=False):
   wdb = load_words()
 
+  mininum = 3
+  if(no_three):
+    mininum += 1
+
   for w in wdb:
-    if(len(letters) >= len(w) and len(w) >= 3):
+    if(len(letters) >= len(w) and len(w) >= mininum):
       lb = create_bank(letters)
       contains_letters = True
       for l in w:
@@ -40,4 +44,15 @@ def main(letters):
         print(w)
 
 if(__name__ == '__main__'):
-  main('catlle')
+  if(len(argv) > 1):
+    if(len(argv) > 2):
+      if(argv[2] == '--no-three' or argv[2] == '-n'):
+        main(argv[1], True)
+      elif(argv[1] == '--no-three' or argv[1] == '-n'):
+        main(argv[2], True)
+      else:
+        print('Usage: python find_words.py [letters] [-n | --no-three]')
+    else:
+      main(argv[1])
+  else:
+    print('Usage: python find_words.py [letters] [-n | --no-three]')

import_dictionary.py

@@ -1,5 +1,5 @@
 def load_words():
-    with open('words_alpha.txt') as word_file:
+    with open('wordlist.txt') as word_file:
         valid_words = set(word_file.read().split())
 
     return valid_words

readme.md

@@ -1,2 +1,3 @@
 ### I forgot how to do headings in markdown and I'm too lazy to look it up
-Word database and python script from: https://github.com/dwyl/english-words
+Word database python script from: https://github.com/dwyl/english-words
+Words list: http://www-personal.umich.edu/~jlawler/wordlist.html